X^2-2x-37=-x+5

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Solution for X^2-2x-37=-x+5 equation:



X^2-2X-37=-X+5
We move all terms to the left:
X^2-2X-37-(-X+5)=0
We add all the numbers together, and all the variables
X^2-2X-(-1X+5)-37=0
We get rid of parentheses
X^2-2X+1X-5-37=0
We add all the numbers together, and all the variables
X^2-1X-42=0
a = 1; b = -1; c = -42;
Δ = b2-4ac
Δ = -12-4·1·(-42)
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-13}{2*1}=\frac{-12}{2} =-6 $
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+13}{2*1}=\frac{14}{2} =7 $

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